(6x^2-2x+50+(2x^2-7x-11)=

Solution for (6x^2-2x+50+(2x^2-7x-11)= equation:

(6x^2-2x+50+(2x^2-7x-11)=

We move all terms to the left:

(6x^2-2x+50+(2x^2-7x-11)-()=0


We calculate terms in parentheses: +(6x^2-2x+50+(2x^2-7x-11)-(), so:

6x^2-2x+50+(2x^2-7x-11)-(

determiningTheFunctionDomain
6x^2-2x+(2x^2-7x-11)+50-(

We add all the numbers together, and all the variables

6x^2-2x+(2x^2-7x-11)

We get rid of parentheses

6x^2+2x^2-2x-7x-11

We add all the numbers together, and all the variables

8x^2-9x-11

Back to the equation:

+(8x^2-9x-11)


We get rid of parentheses

8x^2-9x-11=0

a = 8; b = -9; c = -11;
Δ = b2-4ac
Δ = -92-4·8·(-11)
Δ = 433
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{433}}{2*8}=\frac{9-\sqrt{433}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{433}}{2*8}=\frac{9+\sqrt{433}}{16}
$